Q5. Given:integer x = 40, y = 35, z = 20, w = 10
Comment about the output of the following two statements:
print x * y / z - w
print x * y / (z - w)
a. Differ by 80
b. Same
c. Differ by 50
d. Differ by 160
Answer a.
1.60
2.140 (Difference is 80)
Explanation:
in first Print statement
Operator Precedence in Java
Java has well-defined rules for specifying the order in which the operators in an expression are evaluated when the expression has several operators. For example, multiplication and division have a higher precedence than addition and subtraction. Precedence rules can be overridden by explicit parentheses.
Precedence order.
When two operators share an operand the operator with the higher precedence goes first. For example, 1 + 2 * 3 is treated as 1 + (2 * 3), whereas 1 * 2 + 3 is treated as (1 * 2) + 3 since multiplication has a higher precedence than addition.Associativity.
When an expression has two operators with the same precedence, the expression is evaluated according to its associativity. For example x = y = z = 17 is treated as x = (y = (z = 17)), leaving all three variables with the value 17, since the = operator has right-to-left associativity (and an assignment statement evaluates to the value on the right hand side). On the other hand, 72 / 2 / 3 is treated as (72 / 2) / 3 since the / operator has left-to-right associativity.Precedence and associativity of Java operators.
The table below shows all Java operators from highest to lowest precedence, along with their associativity. Most programmers do not memorize them all, and even those that do still use parentheses for clarity.Oprator | Description | Level | Associativity |
---|---|---|---|
[] . () ++ -- | access array element access object member invoke a method post-increment post-decrement | 1 | left to right |
++ -- + - ! ~ | pre-increment pre-decrement unary plus unary minus logical NOT bitwise NOT | 2 | right to left |
() new | cast object creation | 3 | right to left |
* / % | multiplicative | 4 | left to right |
+ - + | additive string concatenation | 5 | left to right |
<< >> >>> | shift | 6 | left to right |
< <=
> >=
instanceof | relational type comparison | 7 | left to right |
== != | equality | 8 | left to right |
& | bitwise AND | 9 | left to right |
^ | bitwise XOR | 10 | left to right |
| | bitwise OR | 11 | left to right |
&& | conditional AND | 12 | left to right |
|| | conditional OR | 13 | left to right |
?: | conditional | 14 | right to left |
= += -=
*= /= %=
&= ^= |=
<<= >>= >>>=
| assignment | 15 | right to left |
There is no explicit operator precedence table in the Java Language Specification and different tables on the web and in textbooks disagree in some minor ways.
Order of evaluation of subexpressions.
Associativity and precedence determine in which order Java applies operators to subexpressions but they do not determine in which order the subexpressions are evaluated. In Java, subexpressions are evaluated from left to right (when there is a choice). So, for example in the expression A() + B() * C(D(), E()), the subexpressions are evaluated in the order A(), B(), D(), E(), and C(). Although, C() appears to the left of both D() and E(), we need the results of both D() and E() to evaluate C(). It is considered poor style to write code that relies upon this behavior (and different programming languages may use different rules).
Short circuiting. When using the conditional and and or operators (&& and ||), Java does not evaluate the second operand unless it is necessary to resolve the result. This allows statements like if (s != null && s.length() < 10) to work reliably. Programmers rarely use the non short-circuiting versions (&and |) with boolean expressions.